J function

When you see the golden key, π(x) would be related to zeros of Riemann's zeta function. J function is also based on π(x). Therefore, if you counted prime numbers, you would guess zeros of Riemann's zeta function.

ζ(s)=1/(1-1/2^s)×1/(1-1/3^s)×1/(1-1/5^s)×・・・

When s is 0.5+zi, ζ(s)=0.
Here is a Riemann's zero.
s=14.1435657,21.0279853,・・・

In order to use the calculator, you need to put an integer which must be close to 0.5+zi. It is very hard to guess it, because there would be no pattern about it. However, when you calculate J function, you would know that it is almost the same with 0.5+zi. Of course, this isn't perfect. J function is related to prime numbers. The pattern of prime numbers would be fractal, and I can calculate π(x). Therefore, as long as zeros of Riemann's zeta function is connected to π(x), it would move with the same pattern as inflation. I know that the calculation is complicated.

x→J(x)→0.5+zi
40→14.61667→14.1435657
65→21.5333→21.0279853
80→25.28333→25.01585333
105→30.5333→30.42810832
110→32.5333→32.93879514
137→37.5095→37.58932556
153→40.5095→40.92105478





Moreover, when you calculate π(45+10x), 0.5+zi is zeros of Riemann's zeta function and π(45+10x) is almost close to z. The differences between π(45+10x) and z are around 2000?.