You see the circle.
x^2+y^2=1
a/c and b/c are rational.
(a/c)^2+(b/c)^2=1
x=a/c, y=b/c
∴a=cx, b=cy
(1/2)ab=1
This is half of rectangular ab.
a^2+b^2=c^2
(3,4,5) is Congruent number which is rational, but 1 is not.
if ab=2, a=1 and b=2. c is irrational.
This is contradictory.
(1/2)cx*cy=(1/2)c^2*xy=1
You see the rational point P. You put P on x and y.
Then you get an elliptic curve.
Y^2=X^3-X
You use modulo. For example, you see modulo 3.You get x=(0,1,2) because 3 is 0 in modulo. You put it in y^2. y^2=(0,1,4)=(0,1,1) in modulo. Then, x^3-x=(0,0,6)=(0,0,0) in modulo.
You compare y^2 and x^3-x in modulo. You get (0,1,1) and (0,0,0). You see 0 in both side. x=(0,1,2) and y=(0,0,0)
You have 3 in y. This is prime number.
You repeat it over and over again. The sum of y is sometime prime, but you always have prime as modulo. 0 is hopeless but it is only solution according to Fermat.
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